Steady-State Continuous Point Release with No Wind

Case 1 Steady-State Continuous Point Release with No Wind 

Equation 5-10 is more tractable by defining a radius as r2 = x2 + y2 + z2. Transforming Equation 5-10 in terms of r yields 

For a continuous steady-state release the concentration flux at any point r from the origin must equal the release rate Qm (with units of mass/time). This is represented mathematically by the following flux boundary condition  

It is easy to verify by substitution that Equation 5-15 is also a solution to Equation 5-11 and thus a solution to this case. Equation 5-15 is transformed to rectangular coordinates to yield 

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