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Stationary states and multiplicity

The stationary-state solutions are obtained by setting d0p/dr = d0q/dt = 0. These give [Pg.321]

Using the singularity theory approach, we find that the stationary-state locus will display a hysteresis loop provided that [Pg.322]

Again then, we see that if there is no desorption of the reactant P, i.e. if K = 0, the system will display multiplicity, irrespective of the poison Q. [Pg.322]

The reaction processes on the surface are now determined by two coupled equations (12.45) and (12.46). There are two independent concentrations and a cubic non-linearity, hence we expect that Hopf bifurcation may also be a feature of this model. [Pg.322]

For simplicity, we will consider the case without reactant desorption, K = 0, in which analytical expressions for the stationary-state concentrations can be obtained. With K = 0, the stationary-state condition requires [Pg.322]


See other pages where Stationary states and multiplicity is mentioned: [Pg.321]    [Pg.325]   


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