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Stagnation properties

From (a) and (b), the stagnation pressure and temperature can thus be calculated at exit from the cooled row they can then be used to study the flow through the next (rotor) row. From there on a similar procedure may be followed (for a rotating row the relative (7 o)r, i and (po)k replace the absolute stagnation properties). In this way, the work output from the complete cooled turbine can be obtained for use within the cycle calculation, given the cooling quantities ip. [Pg.60]

To solve a particular problem, we must also specify the process. For example, reversible adiabatic flow through a nozzle yields the following familiar expressions relating the properties at some point in the flow to the Mach number and the stagnation properties, i.e., the properties where the velocity is zero ... [Pg.212]

Lian Qiao, with its pungent and aromatic properties, can disperse stagnation and accumulation, but is used here principally... [Pg.247]

Since the herbs that stop bleeding have sour, astringent and cold properties, they may cause blood stagnation and complicate the syndrome. Formulas that stop bleeding should not be used for a long period of time. [Pg.287]

The simplified ERM is very convenient in that all the properties can be evaluated at the stagnation conditions in the reactor. The method may be appropriate for relief sizing for vapour pressure systems when flow is to be via a safety valve. Discharge coefficients for two-phase flow through safety valves are discussed in 9.7.1. -... [Pg.84]

Fig. 2.23 Computational solution to a CVD reactor, stagnation-flow problem. The white arrows illustrate the streamlines, and the color (grayscale) illustrates the temperature field. Flow enters both through a porous showerhead assembly and through an annular channel adjacent to the outer wall. The exhaust exits downward through the annular channel. The process is running at a reduced pressure of 10,000 Pa (approximately one-tenth of atmospheric pressure). The fluid properties are those for air. Fig. 2.23 Computational solution to a CVD reactor, stagnation-flow problem. The white arrows illustrate the streamlines, and the color (grayscale) illustrates the temperature field. Flow enters both through a porous showerhead assembly and through an annular channel adjacent to the outer wall. The exhaust exits downward through the annular channel. The process is running at a reduced pressure of 10,000 Pa (approximately one-tenth of atmospheric pressure). The fluid properties are those for air.
Develop a numerical solution to describe the axisymmetric, semi-infinite, isothermal, stagnation flow of air with strain rates in the range 1/s < a < 1000/s. Solve the problem in physical variables (i.e., not nondimensional) using constant properties evaluated at T = 300 K. [Pg.302]

Derive the nondimensional thermal-energy equation for an axisymmetric, semi-infinite stagnation flow of a constant-property incompressible fluid. [Pg.304]

Stagnation flames are also being used to modify the surface properties of various materials. For example, premixed methane-air flames can beneficially alter the properties of polymer films [41,358,381,382,388]. Flames can also modify surface properties of ferrous and nonferrous metals, for example, improving surface hardness [360] by creating... [Pg.700]

A characteristic of micro channel reactors is their narrow residence-time distribution. This is important, for example, to obtain clean products. This property is not imaginable without the influence of dispersion. Just considering the laminar flow would deliver an extremely wide residence-time distribution. The near wall flow is close to stagnation because a fluid element at the wall of the channel is, by definition, fixed to the wall for an endlessly long time, in contrast to the fast core flow. The phenomenon that prevents such a behavior is the known dispersion effect and is demonstrated in Figure 3.88. [Pg.489]

The first deep basin downstream of the entrance sills is the Bornholm Basin (Fig. 10.1). This basin has a maximum depth of more than 90 m and is separated from the next downstream basin by the Slupsk Sill (sill depth 60 m). The buffering properties of the Bornholm Basin play an essential part for the effectiveness of MBls in other central basins. The thermohaline conditions in the Bornholm Basin are also considerably important for the evolution of stagnation in the central Baltic deepwater. In general, there is a frequent inflow of lower amounts of highly saline water that penetrates across the sills into the ArkonaBasin during each baroclinic or weak barotropic inflow event. This water is trapped into the... [Pg.268]


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See also in sourсe #XX -- [ Pg.253 ]




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