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Solution of the Linearized P-B Equation

The rather messy-looking linearized P-B equation (3.21) can be tidied up by a mathematical trick. Introducing a new variable /U defined by [Pg.239]

To solve this differential equation, it is recalled that the differentiation of an exponential function results in the multiplication of that function by the constant in the exponent. For example. [Pg.240]

if fi is an exponential function of r, one will obtain a differential equation of the form of Eq. (3.25). In other words, the primitive or origin of the differential equation must have had an exponential in Kr. [Pg.241]

Two possible exponential functions, however, would lead to the same final differential equation one of them would have a positive exponent and the oto a negative one [Eq. (3.26)]. The general solution of the linearized P-B equation can therefore be written as [Pg.241]

The constants is evaluated by using the boundary condition that far enough from a central ion situated at r = 0, the thermal forces completely dominate the Coulombic forces, which decrease as and there is electroneutrality (i.e., the elechostatic potential vanishes at distances sufficiently far from such an ion, v r 0 as r °°). This condition would he satisfied only if S = 0. Thus, if B had a finite value, Eq. (3.28) shows that the electrostatic potential would shoot up to infinity (i.e., physically unreasonable proposition. Hence, [Pg.241]


By assuming that ions can be regarded as point charges, the solution of the linearized P-B equation turns out to be (Fig. 3.37)... [Pg.289]


See other pages where Solution of the Linearized P-B Equation is mentioned: [Pg.239]   


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