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Solutes mass of solute

Plan The molarity of a solution is the number of moles of solute divided by the number of liters of solution (Equation 13.8). The number of moles of solute (CyHg) is calculated from the number of grams of solute and its molar mass. The volume of the solution is obtained from the mass of the solution (mass of solution = mass of solute -I-mass of solvent = 5.0 g -I- 225 g = 230 g) and its density. [Pg.548]

The teacher should dissolve 10.0 g of CuS04 in 90.0 g of distilled water, H20 (1.0 ml H20 = 1.0 g). This results in a 10% solution of CuS04. Calculate the mass percent of this solution (mass of solute in grams, 10.0, divided by mass of solution in grams, 10.0/100.0 =. 100, multiplied by 100 to find percent) to verify that it is a 10% solution. Observe the color. [Pg.54]

Mass of solution — mass of solute = mass of solvent... [Pg.554]

Percent by mass mass of solute mass of solution ... [Pg.462]

In each case we consider one liter of solution, mass of solution = volume x density... [Pg.315]

Give an equation that relates molar concentration, volume of solution, mass of solute, and molar mass of solute. [Pg.273]

Molarity (Af) amount (mol) of solute volume (L) of solution amount (mol) of solute mass (kg) of solvent mass of solute mass of solution volume of solute... [Pg.404]

Using the definition of mass percent, we have Mass of solute Mass of solution... [Pg.669]

See other pages where Solutes mass of solute is mentioned: [Pg.103]    [Pg.103]    [Pg.98]    [Pg.173]    [Pg.1300]    [Pg.705]    [Pg.290]    [Pg.170]    [Pg.483]    [Pg.167]    [Pg.362]    [Pg.403]    [Pg.498]    [Pg.480]    [Pg.481]    [Pg.399]    [Pg.30]    [Pg.569]    [Pg.45]    [Pg.51]    [Pg.403]    [Pg.1121]    [Pg.300]    [Pg.315]    [Pg.317]    [Pg.317]    [Pg.428]   
See also in sourсe #XX -- [ Pg.642 ]



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