Remarks on deflagrations

At e = T, equation (5-19) shows that dx/d = 0, while the derivative of equation (5-19) shows that d xjdi — —de/d. Since equations (5-33) and (5-34) imply that dtjd 0, it follows that x begins to decrease as (or e) increases, and therefore x becomes less than e. Once e exceeds t, equation (5-36) shows that t continues to decrease as e (or ) increases. Hence x will not approach the required hot-boundary condition t = 1 at = 1. We may therefore conclude that solutions to equations (5-35) and (5-36) cannot satisfy the boundary conditions for strong deflagrations. 

For ordinary deflagration waves, Mq is very small compared with unity and the Rayleigh line is very nearly a straight line with slope d a. x)/d(p = 

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