Nuclei that can be studied by NMR

In a nuclide represented by the nucleus will have a non-zero spin number /, if the number of protons Z and the number of neutrons A, are not both even numbers. H, gC, have, for example, a spin number I = 

1/2 while 7=1 for (deuterium D) or N. All these nuclei will give an NMR signal. Alternatively, the nuclei gC, He, gO, j Si, S which have a spin number of zero, cannot be studied by NMR. In fact, more than half of the stable nuclei known (at least one isotope per element) leads to an NMR signal although the sensitivity varies enormously depending upon the nucleus. 

the protons (the common name for H), or F, are easier to detect than C, which is much less sensitive and also for the reason that it represents only 1 per cent of elemental carbon. 

At a macroscopic scale, even the smallest quantity of a compound is composed of a gigantic number of individual molecules. The number of nuclei being so high, the NMR signal reflect their statistical behaviour, as in optical spectroscopy. 

When these nuclei are placed in a strong external magnetic field Bq (OZ orientation) an interaction will occurs between each individual nuclear magnetic vector and this field. 

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The list of nuclei in the previous question are just commonly used ones in NMR experiments. Other elements are observable, but sometimes these require special hardware to obtain useful signal levels. Some of these other nuclei that can be studied by NMR are 1 0,29Si, 33S, 7 Se, 9Y, i 3Rh, ii7Sn, n Sn, i spt, mcd, Cd, i29Xe, 203T1, 205T1, and o Pb. 

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