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Nonremovable part

Figure 4. Same as Figure 3 for transverse (nonremovable) part of the ab initio 6rst-derivative coupling vector 6, obtained using the all-Dirichlet boundary conditions. [Pg.203]

Figure 3. Transverse (nonremovable) part of the ab initio first-derivative coupling vector, tra (p> 4>x) function of (()). for p = 4, 6, and 8 b and (a) 0 = 1° (near-conical intersection... Figure 3. Transverse (nonremovable) part of the ab initio first-derivative coupling vector, tra (p> 4>x) function of (()). for p = 4, 6, and 8 b and (a) 0 = 1° (near-conical intersection...
Can the nonremovable part also exhibit singularities as one approaches a conical intersection The nonremovable part of the derivative couplings originates from the fact that the gauge field tensor does not vanish [see Eqs. (34) and (35) and text]. Since by construction this tensor assumes only finite values, there is no reason to expect the nonremovable part to exhibit singularities at conical intersections, see also the discussion in Ref 32 and explicit examples in Ref 5. Let us briefly consult Eq. (40) in a conical... [Pg.20]

In other words, solving the Poisson differential equation (26) for the mixing angle o(Q) does not suffer from the integration problem in Eq. (21) since the nonremovable part F has been eliminated from the right hand side of... [Pg.186]


See other pages where Nonremovable part is mentioned: [Pg.197]    [Pg.301]    [Pg.306]    [Pg.301]    [Pg.19]    [Pg.19]    [Pg.1894]    [Pg.197]    [Pg.301]    [Pg.306]    [Pg.301]    [Pg.19]    [Pg.19]    [Pg.1894]    [Pg.215]    [Pg.769]    [Pg.25]    [Pg.7]    [Pg.61]    [Pg.319]    [Pg.110]    [Pg.146]    [Pg.35]    [Pg.150]    [Pg.25]    [Pg.319]    [Pg.817]    [Pg.366]   
See also in sourсe #XX -- [ Pg.19 , Pg.20 ]




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