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More Complex Molecules Contain Polar Bonds and Still Be Nonpolar

Can More Complex Molecules Contain Polar Bonds and Still Be Nonpolar  [Pg.348]

We will simplify the math in this analysis by assigning the vectors representing the three identical B—F bonds an arbitrary magnitude of 1.00. The X, y coordinates for the end of arrow 1 are (0, 1.00). Determining the coordinates for the ends of arrows 2 and 3 requires the use of trigonometric functions. You may have learned the mnemonic SOH CAH TO A, where the letters stand for [Pg.348]

The X coordinate for the end of arrow 2 corresponds to the length of the line opposite the 60° angle. The hypotenuse of the triangle has a length of 1.00 (the arbitrarily assigned value). Therefore, using SOH, [Pg.348]

The magnitude of the y coordinate corresponds to the length of the line adjacent to the 60° angle. Using TOA, [Pg.348]

SO the y coordinate for the end of arrow 2 is -0.500. (The trigonometric formula gives us the length of the side. We know from the diagram that the sign of thisy component is negative.) [Pg.348]




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And bond polarity

Be 1-complex

Bond and bonding polar

Bond and bonding polarity

Bond polarity

Bond polarity molecules

Bond polarization

Bonding bond polarity

Bonding molecules

Bonding nonpolar

Bonding polar bonds

Bonding polarity and

Complexes Containing

Container molecule

Molecule polarity

Molecules complex

Molecules polar molecule

Molecules, polar and nonpolar

Nonpolar

Nonpolar bond

Nonpolar molecules

Nonpolar polar

Nonpolarized

Polar and Nonpolar Bonding

Polar and nonpolar bonds

Polar bonds

Polar bonds and molecules

Polarity bonds and molecules

Polarization complex

Polarized bond

Polarized bonding

Polarized molecules

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