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Middle thirds elimination

Indeed, the logistic map for r > 4 also leads to a middle thirds elimination process, although now the middle thirds axe not exactly thirds any more. In fact, the length of the interval that leaves A after the first application of /s is 1/ 0.45. But topologically there is no difference compared with the Cantor elimination process. Therefore, in analogy to the tent map, we expect to see exponential decay of A induced by /5. This is indeed the case. An analytical approximation to the decay constant is obtained if we assume that the fraction of points that leave A in every step is the same as the firaction that leaves after the first application of fs. With this assumption we obtain Psin) = exp(—771), where 7 = ln[- /5/(- /5 — 1)]. [Pg.55]

An alcohol can be viewed as the product of the first step in the oxidation of a hydrocarbon, in the sense that the overall result can be considered to be the insertion of one O atom between C and H. If another O atom is inserted on the same C, and H2O eliminated, the result is an aldehyde (if the C was at the end of chain) or a ketone (if in the middle). The third step, inserting the last possible O atom on the C of an aldehyde, results in an acid. [Pg.231]

In fact, Heinrich suggested that accident prevention should aim to remove or eliminate the middle or third domino, representing the unsafe act, mechanical or physical hazard, thus preventing the accident. [Pg.154]


See other pages where Middle thirds elimination is mentioned: [Pg.99]    [Pg.428]    [Pg.177]    [Pg.306]    [Pg.356]    [Pg.132]    [Pg.104]    [Pg.26]    [Pg.45]    [Pg.260]    [Pg.226]    [Pg.466]    [Pg.269]   
See also in sourсe #XX -- [ Pg.55 ]




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