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Me3Si 2CMeCl

In the initial stages of the investigation, (Me3Si)2CMeCl was thought to be the immediate precursor of (Mc3Si)2C=CH2 because compounds containing the methylidene [Pg.139]

The organometallic reagent MeMgCl abstracts a proton from the C-methyl group and causes the elimination of the Cl substituent from the P-carbon, thus forming a double bond. [Pg.140]

Using magnesium in Et O, the reaction proceeds to (Me3Si)2C = CH2 262 and (Me3Si)2CHMe 2 in a ratio of 43 57. This is explained by means of the reaction scheme  [Pg.140]

Me3Si)2CMeH in 10% yield, (ClMe2Si)2CMeCl appears decidedly more reactive than this. After 40 hours reaction with an excess of MeMgCl (calculated with respect... [Pg.141]

See other pages where Me3Si 2CMeCl is mentioned: [Pg.96]    [Pg.139]    [Pg.140]    [Pg.140]    [Pg.141]    [Pg.141]    [Pg.142]    [Pg.143]    [Pg.143]    [Pg.145]    [Pg.96]    [Pg.139]    [Pg.140]    [Pg.140]    [Pg.141]    [Pg.141]    [Pg.142]    [Pg.143]    [Pg.143]    [Pg.145]   


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