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Mapping of the transition-state wavefunction

Bending excitation of the parent molecule transforms into rotation of the fragment molecule and therefore it is plausible to expect a relationship between the initial excitation and the final rotational state distribution. [Pg.243]

Within the classical approach one proceeds in a way analogous to direct photodissociation  [Pg.245]

1) Construct the rotational excitation function J(70) by starting classical trajectories on the transition line with initial angle 70. [Pg.245]

2) The square of the quantum mechanical wavefunction along the transition line, s(7o) 2, provides the appropriate weighting for each trajectory. [Pg.247]

3) If the excitation function is monotonic it establishes a unique relation 7o(j) between the initial angle and the final angular momentum state. [Pg.247]


See other pages where Mapping of the transition-state wavefunction is mentioned: [Pg.241]   


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