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Lorentz lemma and reciprocity relations

We assume that two sets of sources, ja, j and j are located within a domain Q and that both generate electromagnetic fields of the same frequency w. We denote by and E jH the fields produced by a-type and 6-typc sources, [Pg.225]

Calculating the dot products of equation (8.129) with E , equation (8.132) with H , equation (8.130) with H, and equation (8.131) with E , we obtain the expression [Pg.225]

Now let the radius R of the ball Or tend to infinity. The surface integral over a sphere Cr vanishes due to radiation conditions (8.85) and (8.86), and we arrive at a mathematical formulation of the Lorentz lemma  [Pg.226]

We now can use the Lorentz lemma to derive the reciprocity relations for the Green s electromagnetic tensor. Let us assume that the electric dipoles with moments a and b are located at points with the radius-vectors r and r , [Pg.226]

Substituting expressions (8.135) through (8.137) into the Lorentz lemma (8.134), we find [Pg.226]


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Lemma

Lorentz

Reciprocal relations

Reciprocity relation

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