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Homospin dinuclear systems

For the exchange coupling of homospin systems the allowed molecular states lie between [Pg.622]

In this fortunate case the zero-field Hamiltonian is diagonal, giving rise to energy levels [Pg.623]

Since the (spin) Zeeman operator in the basis set of coupled spin angular momenta functions S Ms) is diagonal as well, then the magnetic energy levels are easy to generate (Table 10.8) [Pg.623]

Energy levels es for a dinuclear homospin system in zero field [Pg.624]

In evaluating the magnetic susceptibility one can apply the magnetisation formula (Chapter 2). Because the second-order derivatives are zero for the isotropic exchange model, a simplification is obtained [Pg.624]


There are 21 combinations of heterospin dinuclear systems between SA = 1/2 and SB = 7/2 local spins. The zero-field energy levels of the coupled systems can be generated in the same way as in the previous case of homospin systems. The result is... [Pg.629]

Fig. 10.6. Magnetisation per dimer versus the applied field for dinuclear homospin systems at T = 4.2K J/k = — 5K (solid), J/k— — 10K (long dashed), J/k = —20K (medium dashed), J/k = — 30 K (short dashed). Fig. 10.6. Magnetisation per dimer versus the applied field for dinuclear homospin systems at T = 4.2K J/k = — 5K (solid), J/k— — 10K (long dashed), J/k = —20K (medium dashed), J/k = — 30 K (short dashed).
Characteristic susceptibility functions for dinuclear homospin systems SA = SB SA F(x)... [Pg.628]

Isotropic exchange in heterospin dinuclear complexes differs from the homospin case in that the second-order van Vleck coefficients are also non-zero. The final formula for the magnetic susceptibility resembles the case of the narrow multiplets for mononuclear systems spin-orbit coupling can be formally substituted by spin-spin (exchange) coupling. However, the local atomic g-tensors should be properly combined into the molecular-state g-tensor. [Pg.698]


See other pages where Homospin dinuclear systems is mentioned: [Pg.622]    [Pg.622]   


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