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14 Faraday Integrators

Coulometry. If it can be assumed that kinetic nuances in the solution are unimportant and that destmction of the sample is not a problem, then the simplest action may be to apply a potential to a working electrode having a surface area of several cm and wait until the current decays to zero. The potential should be sufficiently removed from the EP of the analyte, ie, about 200 mV, that the electrolysis of an interferent is avoided. The integral under the current vs time curve is a charge equal to nFCl, where n is the number of electrons needed to electrolyze the molecule, C is the concentration of the analyte, 1 is the volume of the solution, and F is the Faraday constant. [Pg.52]

If the reaction in the cell proceeds to unit extent, then the charge nF corresponding to integral multiples of the Faraday constant is transported through the cell from the left to the right in its graphical representation. Factor n follows from the stoichiometry of the cell reaction (for example n = 2 for reaction c or d). The product nFE is the work expended when the cell reaction proceeds to a unit extent and at thermodynamic equilibrium and is equal to the affinity of this reaction. Thus,... [Pg.171]

Controlled-potential coulometry involves nearly complete reduction or oxidation of an analyte ion at a working electrode maintained at a constant potential and integration of the current during the elapsed time of the electrolysis. The integrated current in coulombs is related to the quantity of analyte ion by Faraday s law, where the amps per unit time (coulomb) is directly related to the number of electrons transferred, and thus to the amount of analyte electrolyzed. [Pg.408]

In addition, the current efficiency ( current yield ) is typical for an electrolysis process, the fraction of the electrical cell current - or (integrated over the time) the fraction of the transferred charge - which is used to form the product. The theoretical charge transfer for one mol product is given by the Faraday constant F, the charge of one mol electrons, F = 96 485 As/mol = 26, 8 Ah/mol, multiplied by the number of transferred electrons. [Pg.31]

A current through the galvanic cell changes the composition according to Faraday s law. The time integral of the current / dt is a very precise measure of the variation of the concentration of the electroactive component... [Pg.219]

At first glance, the difference may be expected to be a consequence of the fact that R R2 and that, if R R2, we should measure V = V2- But this is not the case. The differential formulation of Faraday s law cannot be helpful in any manner to get rid of the paradoxes given above while the integral formulation, as we shall now see, can be used to understand the difference of measurements performed by each of our two voltmeters. [Pg.594]

Magneto-optical properties of (In,Mn)As and (Ga,Mn)As have been studied in order to elucidate the origin of ferromagnetism as well as to explore the possibility of using these materials as Faraday isolators, suitable for monolithic integration with the existing semiconductor lasers. [Pg.38]

However, analytical methods that analyze the deposit and substrate together, such as PIXE and X-ray fluorescence (XRF), have a serious problem posed by a nonuniform deposit. For an ion beam, such as protons, incident upon an aerosol sample placed 45° to the beam, the ions pass through the sample and are collected in a Faraday cup to provide absolute concentrations. If the exiting radiation, whether it be ions, X-rays, electrons, or light, is uniform across the deposit or if the deposit itself is uniform, then the result is accurate. However, if both the beam and sample are nonuniform in either plane, a convolution integral is required to obtain the concentration on the substrate. In practice this integral is never done, so analytical accuracy is critically dependent on beam and sample uniformity, both of which are usually suspect. [Pg.229]

Applying Faraday s law to Eq. (8) yields the increase of the layer thickness d with time t (Eq. (9)). Its integration yields the growth of d as a function of t. Unfor-... [Pg.284]


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