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Evaluation of the entropy integral for an ideal gas

Since both Cp and R are constant for an ideal gas and Z = 1, integrating equation (16.39) produces [Pg.195]

This is the same result as would have been found by combining the equations pv = / .T and pv = constant, as we would expect. [Pg.195]

Integrating the enthalpy differential between starting and end conditions gives  [Pg.196]

The final enthalpy following a frictionally resisted expansion is given by  [Pg.196]


See other pages where Evaluation of the entropy integral for an ideal gas is mentioned: [Pg.195]   


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