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Energy and Entropy in Solution Formation

Sample Problem 13.1 shows how to predict solubility based on the overall polarity of the solute and the solvent. [Pg.508]

Strategy Consider the structure of each solute to determine whether or not it is polar. For molecular solutes, start with a Lewis structure and apply the VSEPR theory [M Section 9.1]. We expect polar solutes, including ionic compounds, to be more soluble in water. Nonpolar solutes will be more soluble in benzene. [Pg.509]

With four electron domains around the central atom, we expect a tetrahedral arrangement. A symmetrical arrangement of identical bonds results in a nonpolar molecule. [Pg.509]

Crossed arrows can be used to represent the individual bond dipoles [ W Section 9.2]. This molecule is polar and can form hydrogen bonds with water. [Pg.509]

Think About It Remember that molecular formula alone is not sufficient to determine the shape or the polarity of a polyatomic molecule. It must be determined by starting with a conect Lewis structure and apptying the VSEPR theory. [Pg.509]


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