Distillation subregions boundary elements

Let s show that if product points belong to the first and second types boundary elements of distillation subregion RegsH (xD e Regs B andxs RegsM ), then these product points meet the conditions of connectedness (e.g., all these splits are feasible at R = oo and N=oo, product points should lie on these boundary elements). 

Such simplex is analogous to an ideal mixture, components of which correspond to the stationary points of the simplex (in both cases, we have only one bonds chain). That is why at sharp separation, when product points lie in boundary elements of distillation subregion, the set of stationary points (pseudocomponents) is divided into two subsets of stationary points of the top and bottom products, just as at separation of ideal mixture, a set of components is divided into two subsets. 

At sharp separation of azeotropic mixture, the key stationary points key pseudocomponents), that is, stationary points that are adjacent in the bonds chain, play the key components. At separation without distributed pseudocomponents, the set of stationary points Ai, A2... Am is divided into two subsets Ai, A2... A and Ak+i, Ak+i-- Am- These subsets are the boundary elements of distillation subregion Reg , which the top and bottom product points belong to (Rego and Regfl). Dimensionality of these boundary elements is A - 1 and m - (k + 1), correspondingly. The summary dimensionality of these boundary elements is equal to OT -I- 2. 

Which boundary elements of distillation region Reg° or subregion Regy 6 do the product points at R = oo and N=oo belong to ... 

How many types of boundary elements can a distillation subregion Regs 6 have ... 

Can two boundary elements of distillation subregion to which product points at R = 00 and N = oo belong have common stationary points If the answer is yes, then how many common stationary points ... 

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