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Converting mass to volume

These can be used to weigh accurately (p. 22) how much liquid you have dispensed. Convert mass to volume using the equation ... [Pg.11]

Next, you use the density of Ag2S to convert mass to volume. [Pg.803]

Calibration is the process of relating the actual quantity (such as mass, volume, or electric current) to the quantity indicated on the scale of an instrument. Volumetric glassware can be calibrated to measure the volume that is actually contained in or delivered by a particular piece of equipment. Calibration is done by measuring the mass of water contained or delivered and using Table 2-5 to convert mass to volume ... [Pg.48]

To calibrate a 25-mL transfer pipet, first weigh an empty weighing bottle like the one in Figure 2-15. Then fill the pipet to the mark with distilled water, drain it into the weighing bottle, and put on the lid to prevent evaporation. Weigh the bottle again to find the mass of water delivered from the pipet. Use Equation 2-2 to convert mass to volume. Table 2-5 already includes a buoyancy correction. [Pg.48]

We start witii the mass of the liquid and use the density as a conversion factor to convert mass to volume. Flowever, we must use the inverted density expression 1 cm /1.32 g because we want g, the imit we are converting from, to be on the bottom (in the denominator) and cm, the unit we are converting to, on the top (in the numerator). Our solution map takes this form ... [Pg.35]

Notice that density converts cm, a unit of volume, into grams, a unit of mass. Density can also be inverted and used to convert mass to volume. [Pg.61]

Our task is to estimate the volume occupied by one atom of lithium. As usual, the mole is a convenient place to begin the calculations. Visualize a piece of lithium containing one mole of atoms. The molar mass, taken from the periodic table, tells us the number of grams of Li in one mole. The density equation can be used to convert from mass to volume. Once we have the volume of one mole of lithium, we divide by the number of atoms per mole to find the volume of a single atom. [Pg.435]

Dimensional Analysis (start by setting up the ratio of mass to volume, then convert to moles) MH3P04 soln = 0 °857l8 pf)P4°s 1 2 3 4 50ln X 97.99 = 0.0539 MH3P04... [Pg.165]

A—To calculate the molality of a solution, both the moles of solute and the kilograms of solvent are needed. A liter of solution would contain a known number of moles of solute. To convert this liter to mass, a mass to volume relationship (density) is needed. [Pg.192]

Bulk density of soil is the soil weight per unit volume, including water and voids. It is used in converting weight to volume in the mass balance calculations. [Pg.54]

Calculate the volume of activated carbon required. To obtain this volume vAC, divide the amount of TCE to be adsorbed by the adsorption capacity of the carbon, and convert from mass to volume by taking into account the bulk density of the carbon ... [Pg.513]

To convert from volume to mass or from mass to volume of a substance, use the density of the substance as the conversion factor. Keep in mind that the units you want to cancel should be on the bottom of your conversion factor. [Pg.326]

Note Knowledge of the volume of the vessel is not required. However, we could have converted mass to concentration, solved for the new concentration at 1.5 h. and finally converted back to the new (remaining) mass. But this is not necessary... [Pg.665]

Volume is written to 3 significant figures, such as 1.00 cc, to match the 3 significant figures in the mass. As conversion factors, densities can be used to convert a known volume to mass or a known mass to volume. [Pg.27]

If one of the solutes is a liquid, we can use its density to convert its mass to volume and vice versa. For example, a typical American beer contains 5.0% ethanol (CH3CH2OH) by volume in water (along with other components). The density of ethanol is 0.789 g/mL. Therefore, if we wanted to calculate the molarity of ethanol (usually just called alcohol in everyday language) in beer, we would first consider 1.00 L of beer. [Pg.148]

Density can be used as a conversion factor from mass to volume or from volume to mass. To convert between volume and mass, use density directly. To convert between mass and volume, invert the density. [Pg.44]

We convert the mass of Ca + from mg to g, find the mass ratio of Ca + to pill, and multiply by 10 to obtain ppm. (b) We know the volume % (11.5%, or 11.5 parts by volume of alcohol to 100. parts of chianti) and the total volume (0.750 L), so we use Equation 13.7 to find liters of alcohol, (c) We know the mass and formula of each component, so we convert masses to amounts (mol) and apply Equation 13.8 to find the mole fractions. [Pg.406]

The graph shows how to convert from mass to volume fraction or vice versa for a fibre composite. [Pg.349]

Convert from mass to volume (in cm ) using density as a conversion factor. [Pg.74]

More recently, mass distributions have been replaced by volume [35] or area distributions [15, 17] the latter approach takes the two-dimensional area of the wear particles and converts it to volume assuming a constant particle thickness [45]. [Pg.412]

We need the factor 1000 g/kg to convert from kilograms to grams. Density provides the factor to convert from mass to volume. But in this instance, we need to use density in the inverted form. That is. [Pg.14]

The central focus is again the conversion of a measured quantity to an amount in moles. Because the density is given in g/mL, it will be helpful to convert the measured volume to milliliters. Then, density can be used as a conversion factor to obtain the mass in grams, and the molar mass can then be used to convert mass to amount in moles. Finally, the Avogadro constant can be used to convert the amount in moles to the number of molecules. In summary, the conversion pathway is /xL L g — mol molecules. [Pg.75]

Note that a statistical study could be done on an electron micrograph like that shown in Fig. 1.1. The dimensions of the blobs could be converted to volumes and then to masses with a knowledge of the density of the deposited polymer. This approach could be organized into a table of classified data from which any of these averages could be calculated. [Pg.43]

The diametei of average mass and surface area are quantities that involve the size raised to a power, sometimes referred to as the moment, which is descriptive of the fact that the surface area is proportional to the square of the diameter, and the mass or volume of a particle is proportional to the cube of its diameter. These averages represent means as calculated from the different powers of the diameter and mathematically converted back to units of diameter by taking the root of the moment. It is not unusual for a polydispersed particle population to exhibit a diameter of average mass as being one or two orders of magnitude larger than the arithmetic mean of the diameters. In any size distribution, the relation ia equation 4 always holds. [Pg.127]

The molality is the concentration of solute in moles per kilogram of solvent. Its value is independent of the temperature and is directly proportional to the numbers of solute and solvent molecules in the solution. To convert molarity to molality, we note that the former is defined in terms of the volume of the solution, so we convert that overall volume to the mass of solvent present. [Pg.449]

We have information about molarity (mol/L) and density (g/mL) and are asked to find molality (mol/kg) and mole fraction (mol/mol). A good way to approach conversions from molarity to another measure is to choose a convenient volume for the solution, determine its mass and the mass of solute, and find the mass of water by difference. Then convert mass of water to kilograms and to moles to complete the calculations. [Pg.833]

Using 2 unit factors, (1) Convert mass of ammonia to mass of solution using the definition of % by mass, then (2) Convert mass of solution to volume (in mL) of solution using density... [Pg.18]

Equation 21.3-16 may be used to convert rate constants from a mass to a particle volume basis for calculation of the Thiele modulus (eg., equation 8.5-20b). In this chapter, (—rA) without further designation means ( -rA)m. [Pg.522]


See other pages where Converting mass to volume is mentioned: [Pg.160]    [Pg.159]    [Pg.160]    [Pg.159]    [Pg.170]    [Pg.1474]    [Pg.405]    [Pg.406]    [Pg.405]    [Pg.406]    [Pg.407]    [Pg.45]    [Pg.378]    [Pg.1758]    [Pg.633]    [Pg.234]    [Pg.365]    [Pg.33]   
See also in sourсe #XX -- [ Pg.155 ]

See also in sourсe #XX -- [ Pg.155 ]




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Volume-to-mass

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