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Consecutive integers quadratic equations

Write the two consecutive integers as n and n + 1. Multiply them together and set the equation equal to 20. You get a quadratic equation that s solved by setting the equation equal to 0, factoring, and solving for the numbers. [Pg.164]

The quadratic equation gives you two different answers. When n = 4, you get the two consecutive integers 4 and 5. The product of 4 and 5 is, indeed, 20. But what about the solution n = -5 If n = -5, then n+l=-5+l = -4. The product of -5 and -4 is also 20. This problem has two different solutions. As long as you re happy with negative integers, too, then you accept both sets of answers. [Pg.164]

The product of the two consecutive odd integers is written as rt(n + 2). Set that product equal to 143, set the equation equal to 0, and solve the quadratic equation that results. [Pg.165]


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