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Angular Momentum in Molecular Rotation—The Rigid Rotor

4-7 Angular Momentum in Molecular Rotation—The Rigid Rotor [Pg.117]

We have seen that the two-particle system of an electron and a nucleus rotating about a center of mass (COM) can be transformed to the one-particle system of a reduced mass rotating about a fixed point. However, this transformation can be made for any two-mass system, and so it applies also to the case of the nuclei of a rotating diatomic molecule. As we now show, the mathematical outcome for the rotating diatomic molecule is strikingly similar to that for the hydrogenlike ion. [Pg.117]

The simplest treatment of molecular rotation ignores vibrational motion by assuming that the distance between the nuclei is fixed. The resulting model is therefore called the rigid-rotor model. Let there be two nuclear masses, mi and m2, separated from the COM by distances r and ri, respectively. Then, because of the way that the COM is defined, we have that [Pg.117]

It is not difficult to show (Problem 4-35) that the same moment of inertia results from a reduced mass /x rotating about a fixed point at a distance r = r - - r2. That is, if [Pg.117]

Therefore, solving the problem of a reduced mass 11 rotating about a fixed point at the fixed distance r = ri -h r2 is equivalent to solving the two-mass rigid-rotor problem. In effect, the rotating-diatomic problem is transformed to a particle-on-the-surface-of-a-sphere problem. [Pg.117]




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