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Analyzing a Proton NMR Spectrum

This compound will have the same HDI as a compound with molecular formula C5H10. To he fully saturated, 5 carhon atoms would require (5 X 2) + 2 = 12 H s. According to our calculation, two hydrogen atoms are missing, and, therefore, this compound has one degree of unsaturation. HDI = 1. [Pg.49]

With one degree of unsaturation, the compound must contain either one ring or one double bond, but not both. The compound cannot have a triple bond, as this would require two degrees of unsaturation. [Pg.49]

PROBLEMS Calculate the degree of unsaturation for each of the following molecular formulas 2.36 C6H10O4 2.37 C7H11N 2.38 CsHmOz [Pg.49]

Consider the number of signals and integration of each signal (this gives clues about the symmetry of the compound). [Pg.49]

Analyze each signal (chemical shift, integration, and multiplicity), and then draw fragments consistent with each signal. These fragments become our puzzle pieces that must be assembled to produce a molecular structure. [Pg.49]


See other pages where Analyzing a Proton NMR Spectrum is mentioned: [Pg.323]    [Pg.46]    [Pg.49]    [Pg.49]   


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