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The transition state for a molecule desorbing from the surface is quite different to that of the reacting molecule. The desorbing molecule in its transition state is nearly free from the surface. The molecule can therefore be considered to freely rotate and to move freely parallel to the surface. Hence the activation entropy for desorption is quite large. The ratio of the rate of CO bond cleavage, rdiss, over the rate of desorption is... [Pg.31]

See other pages where Activation entropy for desorption is mentioned: [Pg.114] [Pg.196] [Pg.40]